.. _how-to-set-up-llvm-style-rtti: ====================================================== How to set up LLVM-style RTTI for your class hierarchy ====================================================== .. sectionauthor:: Sean Silva .. contents:: Background ========== LLVM avoids using C++'s built in RTTI. Instead, it pervasively uses its own hand-rolled form of RTTI which is much more efficient and flexible, although it requires a bit more work from you as a class author. A description of how to use LLVM-style RTTI from a client's perspective is given in the `Programmer's Manual `_. This document, in contrast, discusses the steps you need to take as a class hierarchy author to make LLVM-style RTTI available to your clients. Before diving in, make sure that you are familiar with the Object Oriented Programming concept of "`is-a`_". .. _is-a: http://en.wikipedia.org/wiki/Is-a Basic Setup =========== This section describes how to set up the most basic form of LLVM-style RTTI (which is sufficient for 99.9% of the cases). We will set up LLVM-style RTTI for this class hierarchy: .. code-block:: c++ class Shape { public: Shape() {} virtual double computeArea() = 0; }; class Square : public Shape { double SideLength; public: Square(double S) : SideLength(S) {} double computeArea() /* override */; }; class Circle : public Shape { double Radius; public: Circle(double R) : Radius(R) {} double computeArea() /* override */; }; The most basic working setup for LLVM-style RTTI requires the following steps: #. In the header where you declare ``Shape``, you will want to ``#include "llvm/Support/Casting.h"``, which declares LLVM's RTTI templates. That way your clients don't even have to think about it. .. code-block:: c++ #include "llvm/Support/Casting.h" #. In the base class, introduce an enum which discriminates all of the different concrete classes in the hierarchy, and stash the enum value somewhere in the base class. Here is the code after introducing this change: .. code-block:: c++ class Shape { public: + /// Discriminator for LLVM-style RTTI (dyn_cast<> et al.) + enum ShapeKind { + SK_Square, + SK_Circle + }; +private: + const ShapeKind Kind; +public: + ShapeKind getKind() const { return Kind; } + Shape() {} virtual double computeArea() = 0; }; You will usually want to keep the ``Kind`` member encapsulated and private, but let the enum ``ShapeKind`` be public along with providing a ``getKind()`` method. This is convenient for clients so that they can do a ``switch`` over the enum. A common naming convention is that these enums are "kind"s, to avoid ambiguity with the words "type" or "class" which have overloaded meanings in many contexts within LLVM. Sometimes there will be a natural name for it, like "opcode". Don't bikeshed over this; when in doubt use ``Kind``. You might wonder why the ``Kind`` enum doesn't have an entry for ``Shape``. The reason for this is that since ``Shape`` is abstract (``computeArea() = 0;``), you will never actually have non-derived instances of exactly that class (only subclasses). See `Concrete Bases and Deeper Hierarchies`_ for information on how to deal with non-abstract bases. It's worth mentioning here that unlike ``dynamic_cast<>``, LLVM-style RTTI can be used (and is often used) for classes that don't have v-tables. #. Next, you need to make sure that the ``Kind`` gets initialized to the value corresponding to the dynamic type of the class. Typically, you will want to have it be an argument to the constructor of the base class, and then pass in the respective ``XXXKind`` from subclass constructors. Here is the code after that change: .. code-block:: c++ class Shape { public: /// Discriminator for LLVM-style RTTI (dyn_cast<> et al.) enum ShapeKind { SK_Square, SK_Circle }; private: const ShapeKind Kind; public: ShapeKind getKind() const { return Kind; } - Shape() {} + Shape(ShapeKind K) : Kind(K) {} virtual double computeArea() = 0; }; class Square : public Shape { double SideLength; public: - Square(double S) : SideLength(S) {} + Square(double S) : Shape(SK_Square), SideLength(S) {} double computeArea() /* override */; }; class Circle : public Shape { double Radius; public: - Circle(double R) : Radius(R) {} + Circle(double R) : Shape(SK_Circle), Radius(R) {} double computeArea() /* override */; }; #. Finally, you need to inform LLVM's RTTI templates how to dynamically determine the type of a class (i.e. whether the ``isa<>``/``dyn_cast<>`` should succeed). The default "99.9% of use cases" way to accomplish this is through a small static member function ``classof``. In order to have proper context for an explanation, we will display this code first, and then below describe each part: .. code-block:: c++ class Shape { public: /// Discriminator for LLVM-style RTTI (dyn_cast<> et al.) enum ShapeKind { SK_Square, SK_Circle }; private: const ShapeKind Kind; public: ShapeKind getKind() const { return Kind; } Shape(ShapeKind K) : Kind(K) {} virtual double computeArea() = 0; }; class Square : public Shape { double SideLength; public: Square(double S) : Shape(SK_Square), SideLength(S) {} double computeArea() /* override */; + + static bool classof(const Shape *S) { + return S->getKind() == SK_Square; + } }; class Circle : public Shape { double Radius; public: Circle(double R) : Shape(SK_Circle), Radius(R) {} double computeArea() /* override */; + + static bool classof(const Shape *S) { + return S->getKind() == SK_Circle; + } }; The job of ``classof`` is to dynamically determine whether an object of a base class is in fact of a particular derived class. In order to downcast a type ``Base`` to a type ``Derived``, there needs to be a ``classof`` in ``Derived`` which will accept an object of type ``Base``. To be concrete, consider the following code: .. code-block:: c++ Shape *S = ...; if (isa(S)) { /* do something ... */ } The code of the ``isa<>`` test in this code will eventually boil down---after template instantiation and some other machinery---to a check roughly like ``Circle::classof(S)``. For more information, see :ref:`classof-contract`. The argument to ``classof`` should always be an *ancestor* class because the implementation has logic to allow and optimize away upcasts/up-``isa<>``'s automatically. It is as though every class ``Foo`` automatically has a ``classof`` like: .. code-block:: c++ class Foo { [...] template static bool classof(const T *, ::llvm::enable_if_c< ::llvm::is_base_of::value >::type* = 0) { return true; } [...] }; Note that this is the reason that we did not need to introduce a ``classof`` into ``Shape``: all relevant classes derive from ``Shape``, and ``Shape`` itself is abstract (has no entry in the ``Kind`` enum), so this notional inferred ``classof`` is all we need. See `Concrete Bases and Deeper Hierarchies`_ for more information about how to extend this example to more general hierarchies. Although for this small example setting up LLVM-style RTTI seems like a lot of "boilerplate", if your classes are doing anything interesting then this will end up being a tiny fraction of the code. Concrete Bases and Deeper Hierarchies ===================================== For concrete bases (i.e. non-abstract interior nodes of the inheritance tree), the ``Kind`` check inside ``classof`` needs to be a bit more complicated. The situation differs from the example above in that * Since the class is concrete, it must itself have an entry in the ``Kind`` enum because it is possible to have objects with this class as a dynamic type. * Since the class has children, the check inside ``classof`` must take them into account. Say that ``SpecialSquare`` and ``OtherSpecialSquare`` derive from ``Square``, and so ``ShapeKind`` becomes: .. code-block:: c++ enum ShapeKind { SK_Square, + SK_SpecialSquare, + SK_OtherSpecialSquare, SK_Circle } Then in ``Square``, we would need to modify the ``classof`` like so: .. code-block:: c++ - static bool classof(const Shape *S) { - return S->getKind() == SK_Square; - } + static bool classof(const Shape *S) { + return S->getKind() >= SK_Square && + S->getKind() <= SK_OtherSpecialSquare; + } The reason that we need to test a range like this instead of just equality is that both ``SpecialSquare`` and ``OtherSpecialSquare`` "is-a" ``Square``, and so ``classof`` needs to return ``true`` for them. This approach can be made to scale to arbitrarily deep hierarchies. The trick is that you arrange the enum values so that they correspond to a preorder traversal of the class hierarchy tree. With that arrangement, all subclass tests can be done with two comparisons as shown above. If you just list the class hierarchy like a list of bullet points, you'll get the ordering right:: | Shape | Square | SpecialSquare | OtherSpecialSquare | Circle .. _classof-contract: The Contract of ``classof`` --------------------------- To be more precise, let ``classof`` be inside a class ``C``. Then the contract for ``classof`` is "return ``true`` if the dynamic type of the argument is-a ``C``". As long as your implementation fulfills this contract, you can tweak and optimize it as much as you want. .. TODO:: Touch on some of the more advanced features, like ``isa_impl`` and ``simplify_type``. However, those two need reference documentation in the form of doxygen comments as well. We need the doxygen so that we can say "for full details, see http://llvm.org/doxygen/..." Rules of Thumb ============== #. The ``Kind`` enum should have one entry per concrete class, ordered according to a preorder traversal of the inheritance tree. #. The argument to ``classof`` should be a ``const Base *``, where ``Base`` is some ancestor in the inheritance hierarchy. The argument should *never* be a derived class or the class itself: the template machinery for ``isa<>`` already handles this case and optimizes it. #. For each class in the hierarchy that has no children, implement a ``classof`` that checks only against its ``Kind``. #. For each class in the hierarchy that has children, implement a ``classof`` that checks a range of the first child's ``Kind`` and the last child's ``Kind``.